ass2: \bar{h} \neq \hbar
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@ -147,7 +147,7 @@ Reordering and calculating the curl gives:
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\item
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From the derivation of the Ginzburg-Landau theory, we get the following expression for the supercurrent $\vec{J_s}$:
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\[
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\vec{J_s} = -\frac{2e\bar{h}n_s}{m}(\nabla\theta + \frac{2e\vec{A}}{\bar{h}})
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\vec{J_s} = -\frac{2e\hbar n_s}{m}(\nabla\theta + \frac{2e\vec{A}}{\hbar})
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\]
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Using the rigid gauge, we set $\theta = 0$.
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Next, we can equate the previously found supercurrent for our foil to the Ginzburg-Landau found one and reorder to find $\vec{A}$:
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