Final: Implement better tests for integrate in task 2.2
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@ -308,8 +308,8 @@
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"source": [
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"def integrate(yk, x):\n",
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" \"\"\"\n",
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" Numerically integrates function yk over [x[0], x[-1]] using\n",
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" Simpson's rule over the grid provided by x.\n",
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" Numerically integrates function yk over [x[0], x[-1]] using Simpson's 3/8\n",
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" rule over the grid provided by x.\n",
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" \n",
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" Args:\n",
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" yk: function of one numerical argument that returns a numeric\n",
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@ -326,23 +326,17 @@
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" if callable(yk):\n",
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" yk = yk(x)\n",
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" \n",
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" #a, b = yk[0], yk[-1]\n",
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" \n",
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" # The distance h_i = x[i + 1] - x[i] is not necessarily constant. The choice of\n",
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" # partitioning of the interval is subject to mathematical considerations I will\n",
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" # not go into.\n",
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" h = x[1:] - x[:-1]\n",
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" \n",
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" # Instead of summing over something with n/2, we use step size 2,\n",
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" # thus avoiding any issues with 2 ∤ n.\n",
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" #integral = h/3*(a + 2*np.sum(yk[2:-1:2]) + 4*np.sum(yk[1:-1:2]) + b)\n",
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" \n",
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" #integral = 3*h/8*(a + 3*np.sum(yk[2:-1:2]) + 3*np.sum(yk[1:-1:2]) + b)\n",
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" #integral = (b - a)/8*(x[0] + x[-1]) + 3*(x[1:] - x[:-1])/8*( )\n",
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" integral = 0\n",
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" integral += 3/8*(x[1] - x[0])*yk[0]\n",
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" integral += 9/8*yk[1:-1:3]@h[1::3]\n",
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" integral += 9/8*yk[2:-1:3]@h[2::3]\n",
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" integral += 6/8*yk[:-1:3]@h[::3]\n",
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" integral += 9/8*h[1::3]@yk[1:-1:3]\n",
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" integral += 9/8*h[2::3]@yk[2:-1:3]\n",
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" integral += 6/8*h[ ::3]@yk[ :-1:3]\n",
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" integral += 3/8*(x[-1] - x[-2])*yk[-1]\n",
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" #integral = 3/8*( (x[1] - x[0])*yk[0] + np.sum(yk[]) + (x[-1] - x[-2])*yk[-1])\n",
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" return integral"
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]
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},
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@ -363,22 +357,20 @@
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"task": false
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}
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"Exact: 333333333.3333333\n",
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"Integrated: 333333448.1291072\n"
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]
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}
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],
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"outputs": [],
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"source": [
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"def test_integrate():\n",
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" # Test integral 1 of f with F its primitive with integration constant 0\n",
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" f = lambda x: x**2\n",
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" x = np.logspace(0, 3, 10000000)\n",
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" print(\"Exact:\", 1000**3/3)\n",
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" print(\"Integrated:\", integrate(f, x))\n",
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" F = lambda x: x**3/3\n",
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" x = np.logspace(0, 3, 1000000)\n",
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" assert np.isclose(integrate(f, x), F(x[-1]) - F(x[0]))\n",
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" \n",
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" # Test integral 2 of f with F its primitive with integration constant 0\n",
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" f = lambda x: np.sin(2*x)/(2 + np.cos(2*x))\n",
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" F = lambda x: -.5*np.log(np.cos(2*x) + 2)\n",
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" x = np.linspace(0, 10, 1000)\n",
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" assert np.isclose(integrate(f, x), F(x[-1]) - F(x[0]))\n",
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" \n",
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"test_integrate()"
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]
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