2024(2): continue instead of break :')

2024/2/2.py

@@ -0,0 +1,40 @@
+verbose = True
+
+def is_safe(nums):
+	print("is_safe")
+	increasing = (nums[1] - nums[0]) > 0
+	for i in range(1, len(nums)):
+		diff = nums[i] - nums[i - 1]
+		if abs(diff) > 3 or abs(diff) == 0 or increasing != (diff > 0):
+			if verbose:
+				print(f"unsafe: {line}", end="")
+			return False
+	if verbose:
+		print(f"  safe: {line}", end="")
+	return True
+	
+
+safe = 0
+unsafe = 0
+with open("input", "r") as fp:
+	while line := fp.readline():
+		nums = list(map(int, line.split(" ")))
+		if is_safe(nums):
+			safe += 1
+			continue
+
+		# Try omitting one of the numbers.
+		if verbose:
+			print("START try to omit one:")
+		for i in range(len(nums)):
+			new_nums = nums.copy()
+			new_nums.pop(i)
+			if is_safe(new_nums):
+				safe += 1
+				break
+		else:
+			unsafe += 1
+		if verbose:
+			print("STOP trying to omit one.")
+
+print(f"Found {safe} safe and {unsafe} unsafe reports.")

2024/2/README.md

@@ -39,6 +39,7 @@ Analyze the unusual data from the engineers. *How many reports are safe?*
 
 To begin, [get your puzzle input](input).
 
+
 Your puzzle answer was `472`.
 
 The first half of this puzzle is complete! It provides one gold star: *
@@ -64,4 +65,7 @@ Thanks to the Problem Dampener, `4` reports are actually *safe*!
 
 Update your analysis by handling situations where the Problem Dampener can remove a single level from unsafe reports. *How many reports are now safe?*
 
-Answer:
+
+Your puzzle answer was `520`.
+
+Both parts of this puzzle are complete! They provide two gold stars: **