ass5: Now it might be a story
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@ -139,10 +139,12 @@ These quantities are related to the energy band gap around the Fermi surface in
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A nice table summarizing these quantities can be found in \cite[table 10.1, p. 191]{waldram}.
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In this essay, we will take a look at what the penetration depth can tell us about the superconducting energy gap, and will go into measuring the penetration depth.
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The penetration depth $\lambda$ is determined by the superfluid density $n_s$ in the two fluid model.
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As $n_s$ can be related to energy gap $\Delta$\cite[ch. 7]{annett}, so can thus $\lambda$ be.
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It is not the maximum value of $\Delta$ we are after, but more its variation in momentum space.
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The band gap energy $\Delta(k)$ is a useful order parameter for superconductivity.
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It can tell us a lot about what kind of superconductor we are dealing with.
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It is not the maximum value of $\Delta$ we are after, but its variation in momentum space, and more specifically any nodes in it.
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Results on the relation between the nodes of the energy gap and the type of superconducting wave we deal with can be seen in figure \ref{fig:waves}.
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The regions with opposite sign correspond to regions of repulsion, whereas same sign regions have attraction.
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Now it is our job to connect this to $\lambda$.
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\begin{figure}
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\centering
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@ -151,18 +153,23 @@ Results on the relation between the nodes of the energy gap and the type of supe
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\label{fig:waves}
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\end{figure}
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In the weak coupling limit of BCS theory, the coherence length can be related to the gap parameter\cite[ch. 9]{waldram} as
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In the theory by the London theory of superconductivity, the penetration depth is related to the superfluid density $n_s$\cite[ch. 3, ch. 7.5]{annett} (of the superfluid model) as
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\[
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\xi_{BCS} = \frac{\hbar v_F}{\pi\Delta},
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\lambda_L(T) = \sqrt{\frac{m_e^*}{\mu_0e^2n_s(T)}}.
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\]
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for $v_F$ the Fermi velocity.
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BCS describes s-wave superconductors.
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Around the Fermi sphere, we see a constant band gap.
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For other types, this is not the case: there is gap anisotropy.
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If $n_s(T)$ can be related to energy gap $\Delta$, so can $\lambda$, and luckily we can.
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If there is a node in $\Delta(k)$ for some $k$, it means that there will be states available for any energy we put in.
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This in turn implies a linearly increasing relation to $\lambda(T) = \lambda(0) + cT$ for some constant $c$.
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But now the question is how we can measure this gap anisotropy.
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In the weak coupling limit of BCS theory, around the Fermi sphere, we see a constant band gap.
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There thus are no nodes.
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BCS describes s-wave superconductors.
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For other types, this is not the case: there is gap anisotropy.
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A result like in figure \ref{fig:waves} can thus tell us what kind of superconductor we see.
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But now the question is how we can measure this gap anisotropy in practice.
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A hard requirement, is that the probe should be sensitive to the direction of the electron momenta\cite[p.207]{waldram}, for which there are multiple methods.
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We will focus on using $\lambda(T)$ measurements using tunnel diode oscillators (TDO)\cite{ozcan}, as that technique is used in the provided paper.
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We will focus on using $\lambda(T)$ measurements using tunnel diode oscillators (TDO)\cite{ozcan}, as that technique is used in the provided paper, and we just discussed the relation between $\lambda$ and the band gap.
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\bibliographystyle{vancouver}
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\bibliography{references.bib}
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